Riddle: The age of a person in 1998 became equal to the sum of the digits of the year of their birth. How old is this person?

This riddle has been around for some time on internet platforms such as Instagram, Facebook, and WhatsApp, and many people still argue over what the answer might be, as there are many possibilities.

The answer to The age of a person in 1998 riddle is below.

Suppose you are born in 19xy then

1998-1900-10x-y=1+ 9+x+y

Left is the 1998 minus the year of birth

Right expression is the sum of the digits of year of birth

Simplify to get

88=11x+2y

The only digits that satisfy this are

X=8

Y=0

So birth year is 1980

Current age is 41

or

I think most people completely misunderstood the question lmfao.

You can’t do the math if you can’t even get the question right.

The year is 1998 (NOT THE BIRTH YEAR). The info that are not given is the person’s age in 1998, and their birth year.

The birth year is 19XY (where X and Y can take values of 0-9, capped at year 1998)

Possible sum is > 10 and < 28 as it cant be 10 or else it’ll be 1900 and the person would be 98 years.

1998 – 28 = 1971

1998 – 10 = 1988

So Possible birth year is > 1971 and < 1988

Which means X is either 7 or 8.

If X is 7 and Y is odd, the sum would be even but age would be odd. ❌

If X is 7 and Y is even, the sum would be odd but age would be even.❌

Thus, X cant be 7.

If X is 8, and Y is even, sum would be even, and age would also be even. ✅

If X is 8, and Y is odd, sum would be odd, but age would be even. ❌

So possible years would be

1980, 1982, 1986, 1988.

Thus, the birth year is 1980 (1+9+8+0 = 18)

1998 – 1980 = 18

How about year 1976?

Sorry for the previois comment but 1976 is wrong. Thank you.